已知x+1⼀x=3,求下列各式的值。(1)x^2+1⼀x^2 (2)x^4+1⼀x^4

2024-12-19 13:51:47
推荐回答(3个)
回答1:

x^2+1/x^2
=(x+1/x)^2-2
=3^2-2
=9-2
=7

x^4+1/x^4
=(x^2+1/x^2)^2-2
=7^2-2
=49-2
=47

回答2:

已知x+1/x=3, 平方,得 x^2+2+1/x^2=9
x^2+1/x^2=7
x^2+1/x^2=7 平方,得 x^4+2+1/x^4=49
x^4+1/x^4=47

回答3:

你好
很高兴为你解答
x+1/x=3
x+1=3x
2x=1
x=1/2

x^2+1/x^2
=17/4
x^4+1/x^4
=16+1/16=257/16

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