1.4/(x²-1)-(x+1)/(x-1)=-1
解：4-(x+1)²=-(x²-1)
4-x²-2x-1=-x²+1
2x=2
x=1
∵x²-1≠0
∴x≠±1
∴方程无解
2.解：4/(x²-1)-(x+1)/(x-1)
=[4-(x+1)²]/(x²-1)
=(-x²-2x+3)/(x²-1)
=[-(x+3)(x-1)]/[(x-1)(x+1)]
=-(x+3)/(x+1)
第一题,解方程：4/(x^2-1)-(x+1)/(x-1)=-1
4-(x+1)^2=-(x^2-1)
4-x^2-2x-1=-x^2+2x-1
4x=4
x=1
经检验x=1是方程的增根
第二题,计算：4/(x^2-1)-(x+1)/(x-1)
=（4-（x+1)^2)/(x^2-1)
=（4-x^2-2x-1)/(x^2-1)
=-(x^2+2x-3)/(x^2-1)
=-(x+3)(x-1)/(x-1)(x+1)
=-(x+3)/(x+1)
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