(x^2-9分之x+3+6+x-x^2分之x)乘以4x-6分之3-x 怎么做

2025-01-03 22:02:47
推荐回答(1个)
回答1:

(x^2-9分之x+3+6+x-x^2分之x)乘以4x-6分之3-x
=[(x+3)/(x²-9)+x/(6+x-x^2)]×(3-x)/(4x-6)
=[1/(x-3)+x/(x+2)(3-x)]×(3-x)/(4x-6)
=(-1+x/(x-2)]×1/(4x-6)
=(-x+2+x)/(x-2)(4x-6)
=2/(x-2)(4x-6)
=1/(x-2)(2x-3)

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