(x^2-9分之x+3+6+x-x^2分之x)乘以4x-6分之3-x=[(x+3)/(x²-9)+x/(6+x-x^2)]×(3-x)/(4x-6)=[1/(x-3)+x/(x+2)(3-x)]×(3-x)/(4x-6)=(-1+x/(x-2)]×1/(4x-6)=(-x+2+x)/(x-2)(4x-6)=2/(x-2)(4x-6)=1/(x-2)(2x-3) 如有不明白,可以追问如有帮助,记得采纳,谢谢祝学习进步!