java问题,高手帮忙！谢谢

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class shuzhi {

    public static void main(String args[]) throws IOException {
        int g, n1 = 0, n2 = 0, n3 = 0, n4 = 0, n5 = 0, n6 = 0, n7 = 0, n8 = 0, n9 = 0, n0 = 0;

        System.out.println("请输入一个16位数字:");
        //x=(int)System.in.read();
        //x=Integer.parseInt(args[0]);
        BufferedReader bin = new BufferedReader(new InputStreamReader(System.in));
        long x = Long.parseLong(bin.readLine());//16位的应该用long

        //x=(int)bin.readLine( );
        //x=Long.parseLong(bin.readLine( ));
        do {
            g = (int)(x % 10);//这里要做类型转换
            switch (g) {
                case 9:
                    n9++;
                    break;
                case 8:
                    n8++;
                    break;
                case 7:
                    n7++;
                    break;
                case 6:
                    n6++;
                    break;
                case 5:
                    n5++;
                    break;
                case 4:
                    n4++;
                    break;
                case 3:
                    n3++;
                    break;
                case 2:
                    n2++;
                    break;
                case 1:
                    n1++;
                    break;
                case 0:
                    n0++;
                    break;
            }
        } while ((x = x / 10) > 0);//这里的判断不对，应该大于0
        System.out.println(n0 + n1 + n2 + n3 + n4 + n5 + n6 + n7 + n8 + n9);
    }
} 

这种问题不会有人回答的…求给分啦，谢

int类型？16位就溢出了。应该使用long或者double类型，不过相应语句要变一变，而且switch也要换换，使用if写吧。

刚才调试了一下！！
16位的不能用int
用long把
还有do {} while;

后面while的条件应该是这样
while((x=x/10) > 0);