解方程:(1)(x+1) 2 -144=0(2)3(x-2) 2 =x(x-2)(3) 1 2 x 2 - 1 3 x

2025-03-12 01:35:46
推荐回答(1个)
回答1:

(1)∵(x+1) 2 -144=0,
∴(x+1) 2 =144,
∴x+1=±12,
解得:x 1 =11,x 2 =-13;

(2)∵3(x-2) 2 =x(x-2),
∴(x-2)(3x-6-x)=0,
∴(x-2)(2x-6)=0,
即x-2=0或2x-6=0,
解得:x 1 =2,x 2 =3;

(3)∵
1
2
x 2 -
1
3
x-
1
6
=0

∴3x 2 -2x-1=0,
∴(3x+1)(x-1)=0,
即3x+1=0或x-1=0,
解得:x 1 =-
1
3
,x 2 =1;

(4)∵(x+2) 2 -10(x+2)+24=0,
∴(x+2-4)(x+2-6)=0,
即(x-2)(x-4)=0,
即x-2=0或x-4=0,
解得:x 1 =2,x 2 =4.