(1)∵(x+1) 2 -144=0, ∴(x+1) 2 =144, ∴x+1=±12, 解得:x 1 =11,x 2 =-13; (2)∵3(x-2) 2 =x(x-2), ∴(x-2)(3x-6-x)=0, ∴(x-2)(2x-6)=0, 即x-2=0或2x-6=0, 解得:x 1 =2,x 2 =3; (3)∵
∴3x 2 -2x-1=0, ∴(3x+1)(x-1)=0, 即3x+1=0或x-1=0, 解得:x 1 =-
(4)∵(x+2) 2 -10(x+2)+24=0, ∴(x+2-4)(x+2-6)=0, 即(x-2)(x-4)=0, 即x-2=0或x-4=0, 解得:x 1 =2,x 2 =4. |