推荐回答（5个）
-3
设圆为x，方块为y，三角为z，
就得出两个方程：
_x_y=3 _y_z=6
_x_y=1 _y_z=4
运算无非是+或-
假设x+y=3.x-y=1:y+z=6,y-z=4,则x=2,y=1,y=5,z=1，要使y一致，则y=1即可，则z=5，x=2，则根据两个做减法的图形看出，方框小的作减法，其余做加法（或者里面的图形与外面的图形向抵的作减法，不相接触的作加法），所以答案是2+5=7
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