已知关于x,y的多项式(2x^2+mx-0.5y+3)-(3x-2y+1-nx^2)

的值与字母x无关,求多项式(m+3n)-(2m-n)
2025-01-04 12:44:01
推荐回答(3个)
回答1:

(2x^2+mx-0.5y+3)-(3x-2y+1-nx^2)
=2x^2+mx-0.5y+3-3x+2y-1+nx^2
=(2+n)x^2+(m-3)x+1.5y+2
(2x^2+mx-0.5y+3)-(3x-2y+1-nx^2)的值与字母x无关
n+2=0,m-3=0
n=-2,m=3
(m+3n)-(2m-n)=-m+4n=-11

回答2:

含有x的项为0,二次项系数为0,一次项系数为0,求的m、n的值

回答3:

(2x^2+mx-0.5y+3)-(3x-2y+1-nx^2)
=2x^2+mx-0.5y+3-3x+2y-1+nx^2
=(2+n)x^2+(m-3)x+1.5y+2
即2+n=0,m-3=0
即n=-2,m=3
(m+3n)-(2m-n)
=(3+3*(-2))-(2*3-(-2))
=-3-8
=-11