寻结构力学高人 求下图右图中各杆端弯矩是如何求出的。滑动支座不会算。。详细描述见问题补充

2024-12-01 18:44:55
推荐回答(3个)
回答1:

力矩分配法,给D点一个单位位移,用位移法取C点转角为基本未知量,固定C,C点左弯矩为6i/L,分配,C点左、下各为3i/L,再由C点向A(1/2)、D(1/1)传递。

回答2:

当水平梁D竖向位移1时,二端固定时端部弯矩6I/L,C端一次分配(即除以2)3i/L,往A传递系数
-0.5,C点3i/2L,同时C向D传递系数-0.5,D端6I/L-3i/L*-0.5=9i/2 ,DB杆抗弯刚度无限大,不分配6I/L

回答3:

很简单的,相当于求下图的弯矩图。对该图用位移法求解,只有一个未知量 ,求解过程:
1、写出杆端弯矩表达式(线刚度 )

2、列位移法方程

3、解方程求
4、求杆端弯矩:将 代入杆端弯矩表达式,可得你问的数据,做弯矩图注意杆端弯矩以顺时针为正,即得弯矩图如你所给图。

1如需过程,请把电子邮箱留下,给你发过去,这儿上载不了。

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