寻结构力学高人 求下图右图中各杆端弯矩是如何求出的。滑动支座不会算。。详细描述见问题补充
推荐回答（3个）
力矩分配法，给D点一个单位位移，用位移法取C点转角为基本未知量，固定C，C点左弯矩为6i/L，分配，C点左、下各为3i/L，再由C点向A（1/2)、D(1/1)传递。
当水平梁D竖向位移1时，二端固定时端部弯矩6I/L，C端一次分配（即除以2）3i/L,往A传递系数
-0.5，C点3i/2L,同时C向D传递系数-0.5，D端6I/L-3i/L*-0.5=9i/2 ，DB杆抗弯刚度无限大，不分配6I/L
很简单的，相当于求下图的弯矩图。对该图用位移法求解，只有一个未知量 ，求解过程：
1、写出杆端弯矩表达式（线刚度 ）
2、列位移法方程
3、解方程求
4、求杆端弯矩：将 代入杆端弯矩表达式，可得你问的数据，做弯矩图注意杆端弯矩以顺时针为正，即得弯矩图如你所给图。
1如需过程，请把电子邮箱留下，给你发过去，这儿上载不了。
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