已知x分之1-y分之1=3,求代数式x-2xy-y分之2x+3xy-2xy的值=多少

2024-12-19 05:09:25
推荐回答(2个)
回答1:

1/x-1/y=(y-x)/(xy)=3
y-x=3xy
x-y=-3xy

原式=[(x-y)-2xy]分之[2(x-y)+3xy]
=[(-3xy)-2xy]分之[2(-3xy)+3xy]

=(-5xy)分之(-3xy)
=5分之3

回答2:

1/x-1/y=3 两边都乘以xy, 得 y-x=3xy
x-2xy-y=x-y-2xy
=-3xy-2xy
=-5xy
2x+3xy-2y=2x-2y+3xy
=-6xy+3xy
=-3xy
代数式x-2xy-y分之2x+3xy-2y 就等于-3xy/-5xy=3/5