解下列方程:1.(2x+1)^2-10x-5=0 2. y(y-3)=2(3-y) 3. 4(x-2)^2-(3x-1)^2=0 4. (2x+1)^2-3=0

5. 1⼀2t^2+3t=16. (2x-1)(x+3)=47. x^2-5x+4=0
2025-01-08 10:03:38
推荐回答(1个)
回答1:

x=-1/2或x=2
y=-2或y=3
x=1或x=-3
x=(-1±√3)/2