不可以。。
final String hqlString="from user u where max(time)";
return this.getHibernateTemplate().executeFind(new HibernateCallback() {
public Object doInHibernate(Session session)
throws HibernateException, SQLException {
List resultList = session.createQuery(hqlString).setFirstResult(
(pageNow - 1) * PageHelp.pageSize).setMaxResults(
PageHelp.pageSize).list();
return resultList;
}
});
返回的是List
是不是可以进行分组: from ** group by user having max(time)