若x=(√3-√2)⼀(√3+√2),y=(√3+√2)⼀(√3-√2),则3x^2-5xy-3y^2=___ 紧急求助!

2025-01-05 17:05:58
推荐回答(2个)
回答1:

x=(√3-√2)/(√3+√2),y=(√3+√2)/(√3-√2),

xy=1/1=1
x²-y²
=(5-2√6)/(5+2√6)-(5+2√6)/(5-2√6)
=【(5-2√6)²-(5+2√6)²】/(25-24)
=-40√6
所以
3x^2-5xy-3y^2=3x^2-3y^2-5xy=3×(-40√6)-5
=-120√6-5

回答2:

-120√6-5