h(x)=f(x)+g(x)=cos²﹙x＋π/12﹚+1+1/2sin2x
=½＋½cos﹙2x＋π/6﹚+1+½sin2x
=½＋½[cos﹙2x﹚cosπ/6-sin2xsinπ/6]+1+½sin2x
=½[cos﹙2x﹚cosπ/6+sin2xsinπ/6]+3／2
＝½cos﹙2x-π/6﹚+3／2
T（x)=2h(x)-3=cos﹙2x-π/6﹚，x∈﹙0,5π／6﹚
画图可得2x1-π/6=π/3，即x1=π/4，x2=﹣π/4+5π/3=17π/12,
x3=π/4+5π/3=23π/12
解集﹛π/4,17π/12,23π/12﹜
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