1. 19分之7×13+19分之13×31 2.(51分之2+18分之5)×9×17 3.(24分之5+12分之7-3分之2)×48

要过程 请标号那题是哪题很急
2024-12-15 14:47:52
推荐回答(2个)
回答1:

1.
(7×13)/19+(13×31)/19
=(7×13+31×13)/19
=13×(7+31)/19
=13×38/19
=13×2
=26

2.
(2/51+5/18)×9×17
=2×9×17/51 +5×9×17/18
=18/3 +5×17/2
=6 +85/2
=97/2

3.
(5/24+7/12-2/3)×48
=5×48/24 +7×48/12 -2×48/3
=5×2+7×4-2×16
=10+28-32
=6

回答2:

1解:原式=7/19x13+13/19x31
=(7x13+13x31)/19
=13x(7+31)/19
=13x2
=26
2解:原式=(2/51+5/18)x9x17
=2x9x17/51+5x9x17/18
=2x9/3+5x17/2
=6+85/2
=97/2
=48.5
3解:原式=(5/24+7/12-2/3)x48
=5x48/24+7x48/12-2x48/3
=10+28-32
=6