(1+3+5+7...+1993)-(2+4+6+8+...+1992)是怎样解

2024-12-23 14:08:44
推荐回答(1个)
回答1:

(1+3+5+7...+1993)-(2+4+6+8+...+1992)

=(1-2)+(3-4)+(5-6)+(7-8)+...+(1991-1992)+1993
=-1-1-1-1-……-1+1993
=-996+1993
=997