4X4矩阵键盘程序?

2024-12-22 11:29:43
推荐回答(2个)
回答1:

//4*4键盘检测程序,按下键后相应的代码显示在数码管上
#include
sbit beep=P2^3;
sbit dula=P2^6;
sbit wela=P2^7;
unsigned char i=100;
unsigned char j,k,temp,key;
void delay(unsigned char i)
{
for(j=i;j>0;j--)
for(k=125;k>0;k--);
}
unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,
0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
display(unsigned char num)
{
P0=table[num];
// P0=0xff;
dula=1;
dula=0;
P0=0xc0;
wela=1;
wela=0;
}
void main()
{
dula=0;
wela=0;
while(1)
{
P3=0xfe;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xee:
key=0;
break;
case 0xde:
key=1;
break;
case 0xbe:
key=2;
break;
case 0x7e:
key=3;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
beep=0;
}
beep=1;
display(key);
// P0=table[key];
/* P0=0xff;
dula=1;
while(i--);
dula=0;
P0=0xc0;
wela=1;
wela=0;
dula=0;
wela=0;
P0=0xff;
dula=1;
dula=0;
P0=0xc5;
wela=1;
wela=0; */
P1=0xfe;
}
}
P3=0xfd;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xed:
key=4;
break;
case 0xdd:
key=5;
break;
case 0xbd:
key=6;
break;
case 0x7d:
key=7;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
beep=0;
}
beep=1;
display(key);
/* P0=table[key];
dula=1;
// while(100--);
dula=0;
P0=0xc0;
wela=1;
wela=0;
*/ P1=0xfc;
}
}
P3=0xfb;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xeb:
key=8;
break;
case 0xdb:
key=9;
break;
case 0xbb:
key=10;
break;
case 0x7b:
key=11;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
beep=0;
}
beep=1;
display(key);
/* P0=table[key];
dula=1;
// while(100--);
dula=0;
P0=0xc0;
wela=1;
wela=0;
*/ P1=0xf8;
}
}
P3=0xf7;
temp=P3;
temp=temp&0xf0;
if(temp!=0xf0)
{
delay(10);
if(temp!=0xf0)
{
temp=P3;
switch(temp)
{
case 0xe7:
key=12;
break;
case 0xd7:
key=13;
break;
case 0xb7:
key=14;
break;
case 0x77:
key=15;
break;
}
while(temp!=0xf0)
{
temp=P3;
temp=temp&0xf0;
beep=0;
}
beep=1;
display(key);
/* P0=table[key];
dula=1;
// while(100--);
dula=0;
P0=0xc0;
wela=1;
wela=0;
*/ P1=0xf0;
}
}
}
}

回答2:

具体应用在什么方面?要结合硬件的吧。