x^2-(4+ 根号2）x+3+根号2=0(x-3-根号2)(x-1)=0x1=3+根号2x2=1
解：x^2-4x-(根号2)x+3+根号2=0,(x^2-4x+3)-(根号2)(x-1)=0,(x-1)(x-3)-((根号2)(x-1))=0,得：(x-3-根号2)(x-1)=0，解得：x=1或x=3+根号2.
