fxy的二阶偏导数怎么解?

2025-01-06 19:44:00
推荐回答(2个)
回答1:

∂f/∂x=fx=-4cos(2x+y)+sin(x-y)
∂f/∂y=fy=-2cos(2x+y)-sin(x-y)
∂²f/∂x²=fxx=8sin(2x+y)+cos(x-y)
∂²f/∂y²=fyy=2sin(2x+y)+cos(x-y)
∂²f/∂x∂y=fxy(原题这里写错!)=4sin(2x+y)-cos(x-y)
∂²f/∂y∂x=fyx(原题这里写错!)=4sin(2x+y)-cos(x-y)

回答2:

如果这里的变量是xy两个,那么2阶导数有三个:分别是:dx2 dy2 dxdy