sinα+cosα=1/5(sinα+cosα)^2=1+2sinαcosα=1+sin2α=1/25sin2α=-24/25<0,且0<2α<2π,所以3/2π<2α<2π,所以3/4π<α<π (第四象限)(sinα-cosα)^2=1-2sinαcosα=1-sin2α=49/25sinα-cosα=-7/5cos2α=-(sinα-cosα)(sinα+cosα)=7/25
-5/7