a.b.c成等差数列,不妨设a≤b≤c设公差为d,d≥0a=b-d,c=b+d∴(b-d)²+b²+(b+d)²=12∴3b²+2d²=12∴3b²=12-2d²≤12(d=0时,取等号)∴b²≤4 , ∴b≤2∵a,b,c为三角形三边∴a+b>c即b-d+b>b+d∴b>2d, d∴d²∵2d²=12-3b² d²=6-3/2d²∴6-3/2*b²∴7/4*b²>6∴b²>24/7∴b>2√42/7∴b范围是(2√42/7,2]