计算:1⼀a-1 -1-a , (a⼀a^2-b^2-1⼀a+b)÷b⼀b-a(要过程)

2025-01-07 15:49:48
推荐回答(1个)
回答1:

1/a-1 -1-a
=[1-(a-1)(a+1)]/(a-1)
=(2-a^2)/(a-1)

(a/a^2-b^2-1/a+b)÷b/b-a
=[a-(a-b)]/(a^2-b^2)*(b-a)/b
=[b/(a-b)(a+b)][-(a-b)/b]
=-1/(a+b)