焦点弦公式

2025-04-06 00:32:42
推荐回答(2个)
回答1:

椭圆:
(1)焦点弦:A(x1,y1),B(x2,y2),AB为椭圆的焦点弦,M(x,y)为AB中点,则L=2a±2ex
(2)设直线:与椭圆交于P1(x1,y1),P2(x2,y2),且P1P2斜率为K,则|P1P2|=|x1-x2|√(1+K²)或|P1P2|=|y1-y2|√(1+1/K²)
双曲线:
(1)焦点弦:A(x1,y1),B(x2,y2),AB为双曲线的焦点弦,M(x,y)为AB中点,则L=-2a±2ex
(2)设直线:与双曲线交于P1(x1,y1),P2(x2,y2),且P1P2斜率为K,则|P1P2|=|x1-x2|√(1+K²)或|P1P2|=|y1-y2|√(1+1/K²){K=(y2-y2)/(x2-x1)}
抛物线:
(1)焦点弦:已知抛物线y²=2px,A(x1,y1),B(x2,y2),AB为抛物线的焦点弦,则|AB|=x1+x2+p或|AB|=2p/(sin²H){H为弦AB的倾斜角}
(2)设直线:与抛物线交于P1(x1,y1),P2(x2,y2),且P1P2斜率为K,则|P1P2|=|x1-x2|√(1+K²)或|P1P2|=|y1-y2|√(1+1/K²){K=(y2-y2)/(x2-x1)}
焦点弦是由两个在同一条直线上的
焦半径构成的。焦点弦长就是这两个
焦半径长之和。⑴过椭圆焦点F的直线交椭圆于A、B两点,记q=a^2/c-c,是焦准距,
e是离心率。
令|FE|=m,|ED|=n,则m+n=|FD|。当且仅当,时取|CD|最小值2a。定理1
(配极理论的原则),若点P的极线通过点Q,则点Q的极线也通过点P。
扩展资料:
焦点弦是由两个在同一条直线上的焦半径构成的。焦半径是由一个焦点引出的射线与椭圆或双曲线相交形成的。而由于椭圆或双曲线上的点与焦点之间的距离(即焦半径长)可以用椭圆或双曲线离心率和该点到对应的准线之间的距离来表示(圆锥曲线第二定义)。
因此,焦半径长可以用该点的横坐标来表示,与纵坐标无关。这是一个很好的性质。焦点弦长就是这两个焦半径长之和。
此外,由于焦点弦经过焦点,其方程式可以由其斜率唯一确定,很多问题可以转化为对其斜率范围或取值的讨论。(注意斜率不存在的情况!即垂直于x轴!)
参考资料来源:搜狗百科——焦点弦

回答2:

椭圆:
(1)焦点弦:A(x1,y1),B(x2,y2),AB为椭圆的焦点弦,M(x,y)为AB中点,则L=2a±2ex
(2)设直线;与椭圆交于P1(x1,y1),P2(x2,y2),且P1P2斜率为K,则
|P1P2|=|x1-x2|√(1+K²)或|P1P2|=|y1-y2|√(1+1/K²)
双曲线:
(1)焦点弦:A(x1,y1),B(x2,y2),AB为双曲线的焦点弦,M(x,y)为AB中点,则L=-2a±2ex
(2)设直线;与双曲线交于P1(x1,y1),P2(x2,y2),且P1P2斜率为K,则
|P1P2|=|x1-x2|√(1+K²)或|P1P2|=|y1-y2|√(1+1/K²){K=(y2-y2)/(x2-x1)}
抛物线:
(1)焦点弦:已知抛物线y²=2px,A(x1,y1),B(x2,y2),AB为抛物线的焦点弦,则
|AB|=x1+x2+p或|AB|=2p/(sin²H){H为弦AB的倾斜角}
(2)设直线;与抛物线交于P1(x1,y1),P2(x2,y2),且P1P2斜率为K,则
|P1P2|=|x1-x2|√(1+K²)或|P1P2|=|y1-y2|√(1+1/K²){K=(y2-y2)/(x2-x1)}

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