简便计算:(1+2⼀1)×(1-2⼀1)×(1+3⼀1)×(1-3⼀1)×......(1+99⼀1)×(1-99⼀1)=?

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2025-01-06 05:07:42
推荐回答(2个)
回答1:

原试=(1+1/2)(1-1/2)(1+1/3)(1-1/3)……(1+1/99)(1-1/99)
=3/2 * 1/2 * 4/3 * 2/3 * 5/4 * 3/4 *……*100/99 * 98/99
通过观察发现,化简结果只剩下1/2 * 100/99
∴原式=1/2 * 100/99 =50/99

回答2:

(1+2分之1)*(1-2f分之1)*(1+3分之1)*(1-3分之1)……(1+99分之1)*(1-99分之1)
=(1-1/2)(1+1/2)(1-1/3)(1+1/3)……(1-1/99)(1+1/99)
=(1/2)(3/2)(2/3)(4/3)(3/4)(5/4)……(98/99)(100/99)
=(1/2)(100/99)
=50/99