perl 正则匹配中使用$1捕获变量的问题.

2025-02-24 10:00:13
推荐回答(2个)
回答1:

$aaa="1234,5677,3333";
$aaa=~/\d+,(\d+),\d+/; #现在$1中就是5677
print $1."\n";
$bbb="2223,4241,45452";
$bbb=~/(\d+),\d+,\d+/; #现在$1中是2223
print $1;

回答2:

$1每次匹配都会被改写的,
你的写法有问题吧
$bbb=~/(\d+),\d+,\d+/; #