因式分解：解方程 4x눀=（3x-1）눀

4x²-(3x-1)²=0
(2x+3x-1)(2x-3x+1)=0
(5x-1)(-x+1)=0
x=1/5 x=1
1.a²-b²-4a-4b
=(a+b)(a-b)-4(a+b)
=(a+b)(a-b-4)
2.m²-4mn+4n²-4
=(m-2n)^2-4
=(m-2n+2)(m-2n-2)
3.4-x²-2xy-y²
=4-(x²+2xy+y²)
=4-(x+y)^2
=(2+x+y)(2-x-y)
4.ax²-ay²+a²x-a²y
=a(x²-y²)+a²(x-y)
=a(x+y)(x-y)+a²(x-y)
=a(x-y)(x+y+a)
5.a³+2a²b+ab²-a
=a(a^2+2ab+b^2)-a
=a(a+b)^2-a
=a[(a+b)^2-1]
=a(a+b+1)(a+b-1)

4x²=（3x-1）²
4x²-(3x-1)²=0
(2x-3x+1)(2x+3x-1)=0
(-x+1)(5x-1)=0
-x+1=0 5x-1=0
∴x=1或x=1/5

1.a²-b²-4a-4b=(a-b)(a+b)-4(a+b)=(a+b)(a-b-4)

2.m²-4mn+4n²-4=(m-2n)²-4=(m-2n-2)(m-2n+2)

3.4-x²-2xy-y²=4-(x+y)²=(2-x-y)(2+x+y)

4.ax²-ay²+a²x-a²y=a(x²-y²)+a²(x-y)=a(x-y)(x+y)+a²(x-y)=a(x-y)(x+y+a)

5.a³+2a²b+ab²-a=a(a²+2ab+b²)-a=a[(a+b)²-1]=a(a+b-1)(a+b+1)