计算:(a-1⼀a+1)÷ a^2-2a⼀a^2-4 × a+1⼀a^2+3a+2

= =一定要有过程!!
2025-01-05 17:05:17
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回答1:

(a-1/a+1)÷ a^2-2a/a^2-4 × a+1/a^2+3a+2
=(a-1/a+1)* (a+2)(a-2)/ a(a-2) × a+1/(a+1)(a+2)
=(a-1)(a+2)/a(a+1)(a+2)
=(a-1)/ a(a+1)