解:原式=(9x²-6xy+y²)-(8x²-10xy)-(x²+4xy+4y²)
=9x²-6xy+y²-8x²+10xy-x²-4xy-4y²
=-3y²
当x=2009,y=-2时
-3y²=-3*(-2)²=-12
(3x-y)的2次方-2x(4x-5y)-(x+2y)的2次方
=(3x-y)的2次方-(x+2y)的2次方-2x(4x-5y)
=(3x-y+x+2y)(3x-y-x-2y)-8x²+10xy
=(4x+y)(2x-3y)-8x²+10xy
=8x²-10xy-3y²-8x²+10xy
=-3y²
=-3×4
=-12