求证sin^4x-cos^4x=2sin^2x-1

如果可以的话把tan^2x-sin^2x=tan^2xsin^2x帮求证一下
2025-02-24 11:25:50
推荐回答(2个)
回答1:

sin^4x-cos^4x
=(sin^2x-cos^2x)(sin^2x+cos^2x)
=sin^2x-cos^2x
=2sin^2x-1
tan^2x-sin^2x
=sin^2x/cos^2x-sin^2x
=(sin2x-sin^2xcos^2x)/cos^2x
=sin^4x/cos^2x
=tan^2xsin^2x

回答2:

sin^4x-cos^4x
=(sin^2x-cos^2x)(sin^2x+cos^2x)
=sin^2x-cos^2x
=2sin^2x-1