x^2+y^2-4x-10y+29=0x^2-4x+4+y^2-10y+25=0(x-2)^2+(y-5)^2=0x=2 y=5x^y+xy^2=xy(x+y)=2*5(2+5)=70
x^2+y^2-4x-10y+29=0则：(x-2)^2+(y-5)^2=0;(x-2)^2>=0;(y-5)^2>=0所以有x=2;y=5
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