已知x-y=3,xy=-5,求下列各式的值: x^2+y^2,x^2-xy+xy^2,(x+y)^2

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2024-12-21 19:54:27
推荐回答(2个)
回答1:

解:
x^2+y^2
=(x-y)^2+2xy
=3^2-10
=-1
x^2y-xy-xy^2
=xy(x-1-y)
=-5×(3-1)
=-10
(x+y)^2
=(x-y)^2+4xy
=3^2+4×(-5)
=-11

回答2:

(x-y)^2 =x^2 -2xy +y^2 x^2 + y^2 = 19 (x+y)^2 = 29
X^2 -xy + xy^2= -3-(4*根号下29)