x²-3x+1=0
所以x²-3x=-1
x²+1=3x
所以原式=6/(3x)+2(x²-3x)/x
=2/x+2(-1)/x
=2/x-2/x
=0
x²-3x+1=0
x²+1=3x
x²-3x=-1
6/x²+1 + 2x²-6x/x
=6/(3x)+2(x²-3x)/x
=2/x+(-2/x)
=0
x²-3x+1=0 x²+1=3x x²-3x=-1
6/(x²+1)=6/3x=2/x
2x²-6x=2(x²-3x)=-2
6/(x²+1) + (2x²-6x)/x
=2/x-2/x=0
x²-3x=-1；或者x²+1=3x；
=6/(3x) + 2(x²-3x)/x
=2/x+[2*(-1)]/x
=2/x- 2/x=0
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