数学高中必修五数列,给详细过程,可接受图片,满意给采纳!

2024-11-24 17:59:54
推荐回答(2个)
回答1:

an=1/((2n-1)(2n+1))
=(1/2)*((1/(2n-1))-(1/(2n+1)))
Sn=(1/2)(1-(1/3)+(1/3)-(1/5)+……+(1/(2n-1))-(1/(2n+1)))
=(1/2)(1-(1/(2n+1)))
=n/(2n+1)

回答2: