抛物线y=x^2与直线y=x+2围成的图形分别绕x轴和y轴旋转转所得的体积

2024-12-26 21:30:25
推荐回答(2个)
回答1:

y=x+2=x^2

交点(2,4)(-1,1)

绕x轴旋转

就是y=x+2 绕x旋转围成的体积减去y=x^2围城成的体积

第一个是截面积是梯形=(4+1)x(2--1)/2=7.5

v1=7.5^2pai=56.25π

第二个是截面积积分f(y)dx=x^3/3 x从-1到2积分 求得面积=3

v2=3^2pai=9π

v1-v2=47.25pai


绕y旋转

相当于y=x^2 跟y轴 跟y=x+2 围成的面积绕y轴旋转一圈

就是就是y=x^2 绕y旋转围成的体积减去y=x-2围城成的体积

第一个截面积积分y=4-x^2   f(y)dx=4x-x^3/3 x从0到2积分 求得16/3

v1=(16/3)^2pai=256/9π

第二个是截面积是三角形=(4-2)x(2)/2=2

v2=2^2pai=4π

v1-v2=220/9pai

回答2:

我也来凑热闹:围成的图形分别绕x轴和y轴旋转转所得的体积为:45.30和14.07.如图所示:

请核对数据无误后,再采纳如何?

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