先化简,再求值:{(xy-2)^2+4xy-4}⼀(-xy),其中x=1.,y=-1⼀25

2024-12-25 12:10:45
推荐回答(2个)
回答1:

{(xy-2)^2+4xy-4}/(-xy)
={(xy-2)^2+2(xy-2)+1+2xy-1}/(-xy)
={[(xy-2)+1]^2+2xy-1}/(-xy)
={(xy-1)^2+2xy-1}/(-xy)
={(xy)^2-2xy+1+2xy-1}/(-xy)
=(xy)^2/(-xy)
=-xy
=-1*(-1/25)
=1/25

回答2:

[(xy-2)²+4xy-4]/(-xy)
=(x²y²-4xy+4+4xy-4]/(-xy)
=-xy
=-1×(-1/25)
=1/25
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