因式分解(1)a^2-1 (2)a^2+2a+1 (3)-3x^2+6xy-3y^2 (4)8(x^2-2y^2)-x(7x+y)+xy 以上(4)题求详解其余...

2024-12-16 15:52:40
推荐回答(3个)
回答1:

要学好因式分解,首先得掌握几个基本的公式:平方差公式,完全平方和(差)公式,立方和(差)公没御式等等,这些课本上都有,另外团铅了解一下十字相乘法也会对分解因时有枯或岩帮助。
(1)a^2-1=(a+1)(a-1)
(2)a^2+2a+1=(a+1)^2
(3)-3x^2+6xy-3y^2=-3(x-y)^2
(4)8(x^2-2y^2)-x(7x+y)+xy =8x^2-16y^2-7x^2-xy+xy=x^2-16y^2=(x-4y)(x+4y)

回答2:

1) a^2-1= (a-1)(罩乎a+1) [ a²-b²念余=(a-b)(a+b)]
2) a^2+2a+1=(a+1)² [乘法公式 * (a+b)²=a²+b²+2ab]
3) -3x^2+6xy-3y^2
= -(3x²-6xy+3y²)
=-[3(x²-2xy+y²)]
=-3(x-y)²
4) 8(x^2-2y^2)-x(7x+y)+xy
=8x²物高悉-16y²-7x²-xy+xy
=x²-16y²
=x²-(4y)²
=(x-4y)(x+4y)

望采纳···

回答3:

(1)a^2-1=(a+1)(a-1)
(2)a^2+2a+1=(a+1)^2
(3)-3x^2+6xy-3y^2=-3(x-y)^2
(4)8(x^2-2y^2)-x(7x+y)+xy
=8x^2-16y^2-7x^2-xy+xy
=x^2-16y^2
=(x-4y)(x+4y)