(1)=(x+y分之x+2y)乘以(x+2y分之xy)除以(xy分之x+y)
=(x+y分之xy)乘以(x+y分之xy){也就是(x+y分之xy)的平方
=(x²+2xy+y²)分之x²y²
(2)=(ab分之a+b)²除以(a²b²分之b²-a²)
={a²b²分之(a+b)²}乘以{b²-a²分之a²b²}
=b²-a²分之(a+b)²
展开然后得=b-a分之a+b
回答不易,记得采纳
1. =(x+2y/x+y)乘以xy/x+2y乘以(y/xy+x/xy)
=xy/x+y乘以x+y/xy
=1
2. 没来的急看 抱歉