1.(3x-2y)^2-(2x+3y)^2=? 2.(1⼀4x^4y^3-1⼀2x^4Y^5-1⼀6X^3Y^2)⼀(1⼀2x^3y^2)=?

2024-12-20 13:40:19
推荐回答(2个)
回答1:

(3x-2y)^2-(2x+3y)^2
=9x²-12xy+4y²-4x²-12xy-9y²
=5x²-24xy-5y²
=(5x+y)(x-5y)

(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(1/2x^3y^2)
=(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)*(2x^3y^2)
=2/xy-1/xy^2-1/3
=(2y-1-xy^2)/xy^2

回答2:

1.(3x-2y)^2-(2x+3y)^2
=(3x-2y+2x+3y)(3x-2y-2x-3y)
=(5x+y)(x-5y)
2.(1/4x^4y^3-1/2x^4Y^5-1/6X^3Y^2)/(1/2x^3y^2)
==1/12x^3y^2(3xy+6xy^3-2)/(1/2x^3y^2)
=1/6(3xy+6xy^3-2)