(1)1-x눀+2xy-y눀 (2)x눀-y눀-z눀-2yz 分解因式 谢谢

2024-12-29 11:30:13
推荐回答(2个)
回答1:

(1) 1-x²+2xy-y²
=1-(x²-2xy+y² )
=1- (x-y)²
=(1-x+y)(1+x-y)
(2) x²-y²-z²-2yz
=x²-(y²+z²+2yz)
=x²- (y+z)²
=(x+y+z)(x-y-z)

回答2:

(1)1-x²+2xy-y²
=1-(x-y)²
=(1-x+y)(1+x-y)
(2)x²-y²-z²-2yz
=x²-(y+z)²
=(x+y+z)(x-y-z)