(1/x+1)-(1/x+2)=(1/x+3)-(1/x+4)(x+2-x-1)/(x+1)(x+2)=(x+4-x-3)/(x+3)(x+4)1/(x+1)(x+2)=1/(x+3)(x+4)(x+1)(x+2)=(x+3)(x+4)x^2+3x+2=x^2+7x+124x=-10x=-2.5
(1/x+1)-(1/x+2)=(1/x+3)-(1/x+4)通分(x+2)*(x+1)=(x+3)*(x+4)3x+2=7x+124x=-10x=-5/2