解方程(1⼀x+1)-(1⼀x+2)=(1⼀x+3)-(1⼀x+4)

2024-12-16 17:27:50
推荐回答(2个)
回答1:

(1/x+1)-(1/x+2)=(1/x+3)-(1/x+4)
(x+2-x-1)/(x+1)(x+2)=(x+4-x-3)/(x+3)(x+4)
1/(x+1)(x+2)=1/(x+3)(x+4)
(x+1)(x+2)=(x+3)(x+4)
x^2+3x+2=x^2+7x+12
4x=-10
x=-2.5

回答2:

(1/x+1)-(1/x+2)=(1/x+3)-(1/x+4)
通分
(x+2)*(x+1)=(x+3)*(x+4)
3x+2=7x+12
4x=-10
x=-5/2