已知b平方=ac,求证:(a+b+c)(a-b+c)(a平方-b平方+c平方)=a四次方+b四次方+c四次方

2025-01-07 22:24:09
推荐回答(2个)
回答1:

(a+b+c)(a-b+c)(a²-b²+c²)
=(a+b+c)(a+c-b)(a²-ac+c²)
=[(a+c)²-b²](a²-ac+c²)
=(a²+c²+2ac-ac)(a²-ac+c²)
=(a²+c²+ac)((a²-ac+c²)
=(a²+c²)-a²c²
=a^4+c^4+2a²c²-a²c²
=a^4+c^4+a²c²
=a^4+c^4+(ac)²
=a^4+c^4+(b²)²
=a^4+c^4+b^4

回答2:

左边=[(a+c)²-b²](a²-b²+c²)
=(a²+2ac+c²-b²)(a²-b²+c²)
=(a²+b²+c²)(a²-b²+c²)
=(a²+c²)²-b^4
=a^4+2a²c²+c^4-b^4
=a^4+2b^4+c^4-b^4
=a^4+b^4+c^4=右边