已知cos(π+a)=-1⼀2,3π⼀2<a<2π.sin(2π+a)的值

2025-02-21 17:46:31
推荐回答(2个)
回答1:

cos(π+a)=-1/2
-cosa=-1/2
cosa=1/2
3π/2<a<2π
a=5π/3

sin(2π+a)
=sina
=sin5π/3
=-√3/2

回答2:

cos(π+a)=-cosa =-1/2 cosa =1/2 3π/2<a<2π sina>0
sin(2π+a)=sina=√3/2