已知函数f(x)=根号3cos2x+2sinxcosx+1。求f(x)的最小正周期

2024-12-17 16:44:12
推荐回答(2个)
回答1:

∵f(x)=√3cos2x+sin2x+1
=2sin(2x+π/3)+1
∴f(x)的最小周期为π

回答2:

π (-π/4-3π/4)