解不等式组(x-3)(x+2)<(x+3)(x+4) (2x-1)(2x-5)大于或等于4x(x-5)

2025-01-02 11:35:10
推荐回答(3个)
回答1:

(x-3)(x+2)<(x+3)(x+4)
x^2-x-68x>-18
x>-9/4

(2x-1)(2x-5)>=4x(x-5)
4x^2-12x+5>=4x^2-20x
8x>=-5
x>=-8/5

综上,x>=-8/5

回答2:

fcdgvd(x-3)(x+2)<(x+3)(x+4)
x^2-x-68x>-18
x>-9/4

(2x-1)(2x-5)>=4x(x-5)
4x^2-12x+5>=4x^2-20x
8x>=-5
x>=-8/5>=-8/5

回答3:

101010