若25的x次方=2000,80的y次方=2000,求x+y-xy的值

2024-12-28 01:31:49
推荐回答(1个)
回答1:

25^x=2000, 得:x=log25(2000)=lg2000/lg25=3lg2/lg25
80^y=2000, 得:y=log80(2000)=lg2000/lg80=3lg2/lg80
x+y-xy
=3lg2/lg25+3lg2/lg80-3lg2/lg25*3lg2/lg80
=3lg2(lg80+lg25-1)/lg25lg80
=3lg2(3lg2-1)/lg25lg80