根号18-根号2分之9
=√(9*2)-(9*√2)/(√2*√2)
=3√2-(9√2)/2
=(3-9/2)√2
=(-3/2)√2
希望能帮到你O(∩_∩)O
根号18-根号下2分之9等于3√2-√[(9×2)/(2×2)]=3√2-(3√2)/2=(3/2)√2
解:
根号18-根号2分之9
=根号18-根号[(2分之9)*(2分之2)]
=根号18-根号(4分之18)
=根号18-根号4分之根号18
=根号18-1/2(根号18)
=1/2(根号18)
3/2根号2
√18-√9/√2
=3√2-3/√2
=3√2-3/2√2
=3/2√2
3√2-√9/2=3√2-3/2√2=3/2√2