已知x=根号3+1,y=根号3-1,求x方-y方⼀x方y+xy方的值。

2025-01-07 01:30:55
推荐回答(3个)
回答1:

x方-y方/x方y+xy方
=(x+y)(x-y)/[xy(x+y)]
=(x-y)/xy
=[(√3+1)-(√3-1)]/[(√3+1)(√3-1)]
=2/2=1

回答2:

原式=(x+y)*(x-y)/xy(x+y)=(x-y)/xy=1

回答3:

原式化简为x-y/xy,带入计算结果为根号2/2-1/2