解方程2x-1⼀2[x-1⼀2(x-1)]=1⼀3(x-1)

2024-12-20 16:01:58
推荐回答(4个)
回答1:

2x-1/2[x-1/2(x-1)]=1/3(x-1)
2x-1/2x+1/4(x-1)=1/3x-1/3
(3/2)x+(1/4)x-1/4=(1/3)x-1/3
(3/2)x+(1/4)x-(1/3)x=1/4-1/3
(17/12)x=-1/12
x=-1/17

回答2:

-1/17

回答3:

两边都乘以12得,
24x-12x+6(x-1)=8(x-1)化简得
12x=2(x-1)
x=1/5

回答4:

2x-1/2[x-1/2(x-1)]=1/3(x-1)
则题目要求x不能为1
两边同时乘以6(x-1)
化简得9(x-1/2)^2=11/4
3(x-1/2)=+-√11/2
x=1/2+-√11/6
根据我的步骤你自己来试试看,希望我的回答对你有帮助,谢谢!