已知x*x-6x+1=0求x*x⼀x*x*x*x+x*x+1的值

2025-01-07 01:29:21
推荐回答(3个)
回答1:

x²-6x+1=0
等式两边同除以x
x-6+1/x=0
x+1/x=6
x²/(x^4+x²+1)
=1/(x²+1+1/x²)
=1/(x²+2+1/x²-1)
=1/[(x+1/x)²-1]
=1/(36-1)
=1/35

回答2:

要对x是否=-1/6进行讨论吧

回答3:

x*x-6x+1=0,x-6+1/x=0,x+1/x=6
1/x²+x²+1=(x+1/x)²-2+1=6²-1=35