解下列三元一次方程组 2x-y=7(1) 5x+3y-2z=10(2) 3x+4z=4(3)

2024-12-25 17:06:36
推荐回答(5个)
回答1:

(2)*2+(1)得13x+6y=24 与(1)联立
解得x=25分之66
代入(3)解得z=负50分之49
代入(2)得y=负25分之43

回答2:

解:由(1)得:
y=2x+7-----(4)
将(4)带入(2)得:11x-2z=-11---(5)
由(5)和(3)联立
(5)*2+(3)得:x= - 18/25带入(4)得:y=139/25
将x= - 18/25、y=139/25带入(2)得:z=150/25
即:x= - 18/25、y=139/25、z=150/25

回答3:

由(1)得y=2x-7 ①
由(3)得z=1-3/4x ②
把①②代入二得x=2.64 代入(1)和(3)
得y=-1.72 z=-0.92

回答4:

由(1)得y=2x-7
由(3)得z=(4-3x)/4
将y=2x-7,z=(4-3x)/4代入(3)求出x的值,再将x的值分别代入(1),(3)求出y.z的值

回答5:

3个未知数 3个方程肯定能解出来啊

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