已知△ABC为锐角三角形,∠B,∠C的对边分别为b,c,且∠B=45°,b=√2,c=√3. (2)求△ABC的面积S△ABC

2025-01-04 20:03:09
推荐回答(2个)
回答1:

b/sinB=c/sinC
sinC=√3 /2, C=60°
A=105°
求△ABC的面积S△ABC
=0.5bcsinA
=√6X(√6+√2)/8
=(√3+3)/4

回答2:

s=3/4+1/2×√3/4